n small balls each of mass m impinge elastically each secon…

Physics Newton's Laws of Motion Second Law of Motion Single Correct MCQ

Published on: September 12, 2026

n small balls each of mass m impinge elastically each second on a surface with velocity u. The force experienced by the surface will be

mnu

2 mnu

4 mnu

\(\frac{1}{2} m n \mu\)

Text Solution

Verified by Experts

The correct answer is:

\(\frac{\boxed{\boxed{\times}}}{F} = \frac{dp^{\boxed{\triangle}}}{dt} =\) Rate of change of momentum

As balls collide elastically hence, rate of change of momentum of ball = \(n \left[ mu \right] - \left[ mu \right]\) = 2 m n u

i.e. F = 2 m n \nu u

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